WebIn Δ ABC, B is at right angle. Given, AB=24cm BC=7cm using Pythagoras theorem AB 2+BC 2=AC 2 ⇒(24) 2+(7) 2=AC 2 ⇒AC= (24 2)+(7) 2= 576+49= 625 ⇒AC=25CM (i)sin A= ACBC = 257 cos A= ACAB = 2524 (ii)sin C= ACAB = 2524 cos c= ACBC = 257 Was this answer helpful? 0 0 Similar questions If Δ ABC is a right-angled triangle prove that sin 2A+sin … WebSolution: We can use the property that angles opposite to equal sides are equal and then by using angle sum property in triangle ABC we can find the value of ∠B and ∠C. It is given …

In ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm.

WebIn ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine : (i) sin A, cos A (ii) sin C, cos C. Solution: We use the basic formulas of trigonometric ratios to solve the question. … WebJun 23, 2024 · ABC is right angle triangle therefore by Pythagoras theorem:- AB²+BC²=AC² ΑΒ²=AC²−BC² ΑΒ²= (24)²− (10)² ΑΒ²= (24–10) (24+10) AB²=16*36 AB=√16×36 ΑΒ=4×6 ΑΒ=24cm Advertisement Cynefin To find: Area of a Right-angled triangle AB =perpendicular BC=base And, AC=hypotenuse Area of triangle = 1/2 * perpendicular *base nancy radcliffe

D A

WebNov 18, 2024 · For example, an area of a right triangle is equal to 28 in² and b = 9 in. Our right triangle side and angle calculator displays missing sides and angles! Now we know … WebSolution: Question 23. In the given figure, ABC is a triangle, right angled at B and BD⊥AC. If AD = 4 cm and CD = 5 cm, find BD and AB. Solution: Question 24. Equiangular triangles are drawn on sides of right angled triangle in which perpendicular is double of its base. WebOct 10, 2024 · In a A B C, right angled at B, A B = 24 c m, B C = 7 c m. To do: We have to determine s i n C, c o s C. Solution: We know that, In a right-angled triangle A B C with right angle at B, By Pythagoras theorem, A C 2 = A B 2 + B C 2 By trigonometric ratios definitions, s i n C = O p p o s i t e H y p o t e n u s e = A B A C mega weight loss